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<p>To divide two integers in C++, we can write <tt>a/b</tt>.</p>
<p>Now suppose the <tt>/</tt> key was broken on your keyboard, we could compute the answer another way.  
   We could count how many times we have to subtract b from a provided the result is still non-negative.</p>
<p>Write a program that first asks the user (no prompt needed) for <tt>a</tt> and <tt>b</tt> and then
   computes the integer quotient and remainder of <tt>a/b</tt> without using <tt>/</tt>.</p>
<p>You should output the quotient first and the remainder second. For example, given the input: <tt>7 3</tt>
   you should output <tt>2 1</tt>.</p>
<p><strong>You may use whatever loop you deem appropriate</strong>, though we'd like to suggest using a for loop as practice.</p>
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Copied from problem cpp/for/polydeg (author: redekopp@usc.edu)
Copied from problem cpp/for/blastoff (author: redekopp@usc.edu)
Copied from problem cpp/while/blastoff (author: redekopp@usc.edu)
Copied from problem cpp/while/goldilocks (author: redekopp@usc.edu)
Copied from problem cpp/while/sum50 (author: redekopp@usc.edu)
Copied from problem cpp/conditionals/rps (author: redekopp@usc.edu)
Copied from problem cpp/conditionals/taxbrackets (author: redekopp@usc.edu)
Copied from problem cpp/conditionals/nestedec (author: redekopp@usc.edu)
Copied from problem cpp/conditionals/extracredit (author: redekopp@usc.edu)
Copied from problem cpp/control/flag (author: daveagp@gmail.com)
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Engine
Template / Reference solution
 
#include <iostream>
using namespace std;
int main() {
   int a, b;
\[
   cin >> a >> b;
   int q = 0;
   for( ; a >= b; a -= b){
      q++;
   }
   cout << q <<  " " << a << endl;
]\
   return 0;
}
C++ test suite
json list of stdin/args tests
e.g. [{"stdin":"hi", "args":["4", "5"]},
{"stdin":"noargs"}]

to just run once with no input use [{}]
 
[
   {"stdin": "7 3", "args": ""},
   {"stdin": "100 4", "args": ""},
   {"stdin": "6 7", "args": ""},
   {"stdin": "2001 2", "args": ""}
]
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Note: problems are open-source by default (see 'Public permissions'). Assumed license for open problems is Creative Commons 4.0 Attribution-ShareAlike unless specified in 'Remarks'.