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This program reads in integers until the user enters 0. 
Count how many numbered entered are odd and output that total at the end of the program.
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Remarks
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Copied from problem cpp/selection/count-neg (author: redekopp@usc.edu)
Copied from problem cpp/control/countodd (author: redekopp@usc.edu)
Originally by Mark Redekopp (redekopp@usc.edu) and Dave Pritchard (daveagp@gmail.com)
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Engine
Template / Reference solution
 
#include <iostream>
using namespace std;
int main() {
 
   // You may declare avariables below or add any additional
   //  code before the loop starts.
\[      
   int num_odd = 0;
   int value = 1;
]\
   // Use a loop and selection idiom below
 
   \[ while ]\ (  \[ value != 0   ]\ )  {
     cout << "Enter an integer or 0 to quit:" << endl;
     cin >> \[ value ]\;
\[
     if( value % 2 == 1 ){
        num_odd++;
     }
]\
   }
   cout << "You entered " << \[ num_odd ]\ << " odd numbers" << endl;
   return 0;
}
C++ test suite
json list of stdin/args tests
e.g. [{"stdin":"hi", "args":["4", "5"]},
{"stdin":"noargs"}]

to just run once with no input use [{}]
 
[
   {"stdin": "3 6 2 7 1 9 0"},
   {"stdin": "0"},
   {"stdin": "1 3 5 7 0"}
]
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Note: problems are open-source by default (see 'Public permissions'). Assumed license for open problems is Creative Commons 4.0 Attribution-ShareAlike unless specified in 'Remarks'.