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Description html markup shown to student | <p>Implement the logic to decide who wins the classic game of chance: <strong>Rock, Paper, Scissors</strong></p> <p>The user will type:</p> <table <tr> <th>User input</th><th>Meaning</th> </tr> <tr> <td>0</td><td>Rock</td> </tr> <tr> <td>1</td><td>Paper</td> </tr> <tr> <td>2</td><td>Scissors</td> </tr> </table> <p>Recall: </p> <ul> <li>Paper (1) beats rock (0) </li> <li>Scissors (2) beats paper (1)</li> <li>Rock (0) beats scissors (2)</li> <li>If the same choice is made, the result is a tie</li> </ul> <p>Your program will take in the 2 choices of the two players (first player1, then player2) and then output the winner in the format:</p> <p><tt>Winner = P1</tt> ...or... <tt>Winner = P2</tt> ...or... <tt>Tie</tt> </p> |
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Remarks Comments, history, license, etc. | Copied from problem cpp/conditionals/taxbrackets (author: redekopp@usc.edu) Copied from problem cpp/conditionals/nestedec (author: redekopp@usc.edu) Copied from problem cpp/conditionals/extracredit (author: redekopp@usc.edu) Copied from problem cpp/control/flag (author: daveagp@gmail.com) |
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Template / Reference solution |
using namespace std; int main() { int choice1, choice2; cout << "Enter the choices of the 2 players: " << endl; \[ cin >> choice1 >> choice2; if( choice1 == choice2){ cout << "Tie" << endl; } else if( ((choice1 == 0) && (choice2 == 2)) || ((choice1 == 1) && (choice2 == 0)) || ((choice1 == 2) && (choice2 == 1)) ) { cout << "Winner = P1" << endl; } else { cout << "Winner = P2" << endl; } ]\ return 0; } |
C++ test suite json list of stdin/args tests e.g. [{"stdin":"hi", "args":["4", "5"]}, {"stdin":"noargs"}] to just run once with no input use [{}] | [ {"stdin": "0 1", "args": ""}, {"stdin": "0 2", "args": ""}, {"stdin": "1 2", "args": ""}, {"stdin": "1 0", "args": ""}, {"stdin": "2 0", "args": ""}, {"stdin": "2 1", "args": ""} ] |
Solution visibility |
Note: problems are open-source by default (see 'Public permissions'). Assumed license for open problems is Creative Commons 4.0 Attribution-ShareAlike unless specified in 'Remarks'.