CSCI 102 - Fall 2026 Fundamentals of Computation

Sample MT2 Solutions

Trapezoids

trapezoids.cpp

#include <iostream>
using namespace std;

int main()
{
    int b1a, b1b, b2a, b2b;
    cin >> b1a >> b1b >> b2a >> b2b;

    int sum1 = b1a+b1b;
    int sum2 = b2a+b2b;

    if( sum1 == sum2 ) {
        cout << "Equal" << endl;
    }
    else if (sum1 < sum2)  {
        cout << 5*sum1/2.0 << endl;
    }
    else {
        cout << 5*sum2/2.0 << endl;
    } 
    return 0;
}

Reverse Digits

revdig.cpp

// Output digits of input number in reverse order.
// If number is negative, output nothing.

#include <iostream>
using namespace std;

int main()
{
    int num;
    cin >> num;

    if(num >= 0) {
        do {
            cout << num % 10;
            num /= 10;
        } while( num > 0);
        cout << endl;
    }

    return 0;

}

Distance

distance.cpp

#include <iostream>
using namespace std;

// Function to print out the results
// Input: isDistanced = true if all people are at least 6 feet apart
// Input: lineLength = distance from the first to last person in line
// Prints "distanced" or "not distanced" on one line and the
// line length on the next line.
void printResults(bool isDistanced, double lineLength);

int main()
{
    double start, prev, next;

    cin >> prev;
    start = prev;

    bool distanced = true;
    bool first = true;

    while(prev >= 0) {
        cin >> next;
        if(next == -1) break;

        double dist = next-prev;
        if( dist < 6) {
            distanced = false;
        }
        prev = next;

    }
    printResults(distanced, prev-start);
    return 0;

}

// Complete the definition of printResults, whose operation
// is described above the prototype
void printResults(bool isDistanced, double lineLength)
{
    if(isDistanced) {
        cout << "distanced" << endl;
    }
    else {
        cout << "not distanced" << endl;
    }
    cout << lineLength << endl;

}

Duplicates

duplicates.cpp

#include <iostream>
using namespace std;

int main()
{
    int data[250]; // n will be 250 or less

    int n;
    cin >> n;

    for(int i=0; i < n; i++) {
        cin >> data[i];
    }

    int num = 0;
    for(int i=0; i < n; i++) {
        bool foundDuplicate = false;
        for(int j=0; j < n; j++) {
            if(i != j && data[i] == data[j]) {
                foundDuplicate = true;
                break;
            }
        }
        if(!foundDuplicate) {
            num++;
        }
    }
    if(num > 0) {
        cout << "Numbers with no duplicate: " << num << endl;
    }
    else {
        cout << "All numbers have a duplicate" << endl;
    }

    return 0;

}