CSCI 102 - Fall 2026 Fundamentals of Computation

#include <iostream>
using namespace std;

int main()
{
    // declare necessary variables and complete your
    // code below
    double f1, f2, f3, mymin;
    char units;
    cin >> f1 >> f2 >> f3 >> units;

    if(units == 'c') {
        f3 = 9*f3/5 + 32; // anything that ensures appropriate 'double' arithmetic
    }

    // In this approach, it needs to <= to correctly handle ties
    // Look at the implementation carefully when grading to ensure
    // ties are handled correctly.
    if(f1 <= f2 && f1 <= f3) {
        mymin = f1;
    }
    else if( f2 <= f1 && f2 <= f3) {
        mymin = f2;
    }
    else {
        mymin = f3;
    }

    // Your last action should be to output the minimum temperature
    // (in degrees Fahrenheit).  Do not print any text, just the
    // temperature and a newline.
    cout << mymin << endl;

    return 0;
}

#include <iostream>
using namespace std;

int main()
{
    // Declare necessary variables and complete your
    // code below.  Final outputs should be made with
    // just the sum on a single line.

    // Need to initialize sum if code is going to
    // add or subtract from it.
    int sum = 0;

    int val;
    cin >> val;
    while( val != 0 && val != 13) {
        if(val > 0) {
            // If number is divisible by both, the sum will be unchanged
            // because we added and subtracted it.

            // It is fine to have an if..else if.. structure to make
            // mutually exclusive options for divisible by 2 but not 3 and
            // divisible by 3 but not 2.  As long as it works it is fine.
            if(val % 2 == 0) {
                sum += val;
            }
            if(val % 3 == 0) {
                sum -= val;
            }
        }

        // Get next input
        cin >> val;
    }

    // Print the final sum result
    cout << sum << endl;
    return 0;
}

// Function prototype - Complete the definition below
// Description: Function to count how many decimal digits
// an integer requires
// Input parameter: val - A non-negative integer
// Return value: number of decimal digits in 'val'
// Example:  numDigits(192) should return 3.
int numDigits(int val);

int main()
{
    int vals[100];
    int n;
    cin >> n;  // you may assume n is an even number
    // in the range: 0 <= n <= 100

    // write a loop to recieve the n integers of input
    // from the keyboard and then complete the remainder of the
    // code to print 'yes' or 'no', appropriately.
    // You must use the numDigits function by calling it at least once.
    for(int i=0; i < n; i++) {
        cin >> vals[i];
    }

    // Can also use an int to count how many match
    // and then check for n/2 matches at the bottom.
    bool same = true;
    for(int i=0; i < n/2; i++) {
        int nda = numDigits(vals[i]);
        int ndb = numDigits(vals[n/2+i]);
        if(nda != ndb) {
            same = false;
            break;  // not necessary...fine to go through entire array
        }
    }
    if(same == true) {
        cout << "yes" << endl;
    }
    else {
        cout << "no" << endl;
    }

    return 0;
}

// See prototype above for description of 
// this function.
int numDigits(int val)
{
    // Complete the code for this function

    // Solution which handles an input of 0 (returns 1)
    int nDigits = 1;
    while(val >= 10) {
        nDigits++;
        val /= 10;
    }
    return nDigits;
}